\begin{center}
\footnotesize
\setlength{\mylength}{\baselineskip}
\begin{longtable}{rp{0ex}p{9cm}p{0ex}RL}
\caption{Laurent polynomials and selected mutations for bucket 5.}\\

\toprule \multicolumn{1}{c}{{Node}}&& \multicolumn{1}{c}{{Laurent polynomial}} && \multicolumn{2}{c}{{Mutations from Figure~\ref{fig:5a}}} \\ \midrule \endfirsthead

\multicolumn{6}{c}{{\tablename\ \thetable{} -- continued from previous page}} \\ \addlinespace[1.7ex] \midrule \multicolumn{1}{c}{{Node}}&& \multicolumn{1}{c}{{Laurent polynomial}} && \multicolumn{2}{c}{{Mutations from Figure~\ref{fig:5a}}} \\ \midrule \endhead

\midrule \multicolumn{6}{c}{{Continued on next page}} \endfoot

\bottomrule \endlastfoot

34 && $x+y+z+\frac{z^2}{xy}+\frac{3z}{xy}+\frac{3}{xy}+\frac{1}{xyz}$ && $55 \colon {}$ & $\left(x,\frac{(y+z)^2}{xyz^2},\frac{y}{z}\right)$ \bottomspacer \\ \addlinespace[1.1ex]
 \rowcolor[gray]{0.95}
55 && $x+y+\frac{y}{z}+z+\frac{y}{xz^2}+\frac{2}{xz}+\frac{1}{xy}$ && $34 \colon {}$ & $\left(x,\frac{(z+1)^2}{xy},\frac{(z+1)^2}{xyz}\right)$ \spacer \\* \rowcolor[gray]{0.95}
 &&  && $69 \colon {}$ & $\left(\frac{xyz+1}{xz},x,\frac{1}{yz}\right)$ \bottomspacer \\ \addlinespace[1.1ex]
 69 && $xyz^2+xyz+x+y+z+\frac{1}{yz}+\frac{1}{xz}$ && $55 \colon {}$ & $\left(y,\frac{xy}{y+z},\frac{y+z}{xyz}\right)$ \bottomspacer \\ \addlinespace[1.1ex]
 \end{longtable}
\end{center}
